Respuesta :
Answer:
The peak emf of the generator is 40.94 V.
Explanation:
Given that,
Number of turns in primary coil= 11
Number of turns in secondary coil= 18
Peak voltage = 67 V
We nee to calculate the peak emf
Using relation of number of turns and emf
[tex]\dfrac{N_{1}}{N_{2}}=\dfrac{E_{1}}{E_{2}}[/tex]
[tex]E_{1}=\dfrac{N_{1}}{N_{2}}\times E_{2}[/tex]
Where, N₁ = Number of turns in primary coil
N₂ = Number of turns in secondary coil
E₂ = emf across secondary coil
Put the value into the formula
[tex]E_{1}=\dfrac{11}{18}\times67[/tex]
[tex]E_{1}=40.94\ V[/tex]
Hence, The peak emf of the generator is 40.94 V.
