Answer:
The frequency of this photon is [tex]4.57\times10^{14}\ Hz[/tex]
(D) is correct option.
Explanation:
Given that,
Excited states,
[tex]n=3[/tex]
[tex]n=2[/tex]
We need to calculate the wavelength
Using formula for energy
[tex]E=13.6(\dfrac{1}{n^2}-\dfrac{1}{m^2})[/tex]
[tex]E=13.6(\dfrac{1}{4}-\dfrac{1}{9})[/tex]
[tex]E=1.888\ eV[/tex]
[tex]E=1.888\times1.6\times10^{-19}\ J[/tex]
[tex]E=3.0208\times10^{-19}\ J[/tex]
We need to calculate the frequency
Using formula of frequency
[tex]E=hf[/tex]
[tex]f=\dfrac{E}{h}[/tex]
Where, E =energy
[tex]f=\dfrac{3.0208\times10^{-19}}{6.63\times10^{-34}}[/tex]
[tex]f=4.57\times10^{14}\ Hz[/tex]
Hence, The frequency of this photon is [tex]4.57\times10^{14}\ Hz[/tex]
