Answer:
[tex]V_{rms}= 4.42 V[/tex]
Explanation:
A technician uses an aosilloscope to measure the AC voltage across a resistor in a circuit
Oscillating voltage to be a sine wave with peak voltage
[tex]V_{max}= 6.25 V[/tex]
we need calculate rms value of voltage
by formula we can write
[tex]V_{rms}=\frac{V_{max}}{\sqrt{2} }[/tex]
now putting value
[tex]V_{rms}=\frac{6.25}{\sqrt{2} }[/tex]
=4.42 V
therefore, [tex]V_{rms}= 4.42 V[/tex]
Answer:
The rms voltage on a report is 4.42 V.
Explanation:
Given that,
Peak voltage = 6.25 V
We need to calculate the rms voltage
The rms voltage is equal to the peak voltage divided by square root of 2.
Using formula of rms voltage
[tex]V_{rms}=\dfrac{v_{0}}{\sqrt{2}}[/tex]
Where, [tex]V_{0}[/tex] = Peak voltage
Put the value into the formula
[tex]V_{rms}=\dfrac{6.25}{\sqrt{2}}[/tex]
[tex]V_{rms}=4.42\ V[/tex]
Hence, The rms voltage on a report is 4.42 V.
