Answer:
slit width a = 0.0406 mm
Explanation:
given details
wavelength = 672 nm
width of central fringe = 2Y_1 = 0.014 m
Y_1 = 0.007
\lambda = 6.72*10{-7} m
x = 1.7 m
slid width [tex]a = \frac{x\lamda}{Y_1}[/tex]
a = [tex]=\frac{1.7 *6.72*10^{-7}}{0.007}[/tex]
slit width a = 4.06*10^{-4} m
slit width a = 0.0406 mm
