At a given temperature the vapor pressure of pure liquid benzene and toluene are 745 torr and 290 torr, respectively. A solution prepared by mixing benzene and toluene obeys Raoult's law. At this temperature the vapor pressure of benzene over a solution in which the mole fraction of benzene is equal to 0.340 is:

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JannetPalos JannetPalos · Answer 1 · 2019-08-09T14:26:17+02:00

Answer:

Vapour pressure of benzene over the solution is 253 torr

Explanation:

According to Raoult's law for a mixture of two liquid component A and B-

vapour pressure of a component (A) in solution = [tex]x_{A}\times P_{A}^{0}[/tex]

vapour pressure of a component (B) in solution = [tex]x_{B}\times P_{B}^{0}[/tex]

Where [tex]x_{A},x_{B}[/tex] are mole fraction of component A and B in solution respectively

[tex]P_{A}^{0},P_{B}^{0}[/tex] are vapour pressure of pure A and pure B respectively

Here mole fraction of benzene in solution is 0.340 and vapour pressure of pure benzene is 745 torr

So, vapour pressure of benzene in solution = [tex]0.340\times 745 torr[/tex]

= 253 torr