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A small block is released from rest from the edge of a large hemispherical frictionless bowl with radius 3 m. As the mass passes through the bottom of the bowl: 22. Its speed is a) 3.7 m/s b) 4.7 m/s c) 5.7 m/s d) 6.7 m/s e) 7.7 m/s

Respuesta :

Explanation:

It is given that,

Radius of bowl, r = 3 m

A small block is released from rest from the edge of a large hemispherical friction less bowl. Let v is the speed of the mass when it passes through the bottom of the bowl and u is the initial speed of the  mass, u = 0. Using conservation of energy as :

[tex]mgh=\dfrac{1}{2}mv^2[/tex]

h = r = 3 m

[tex]v=\sqrt{2gh}[/tex]

[tex]v=\sqrt{2\times 9.8\ m/s^2\times 3\ m}[/tex]

v = 7.66 m/s

or

v = 7.7 m/s

So, the speed of the mass at the bottom of the bowl is 7.7 m/s. Hence, this is the required solution.

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