Answer:26.7 torr
Explanation:
The answer is 26.7 torr.
We can say that vapor pressure remains same because vapor is calculated by [tex]\ln \frac{P_1}{P_2} = \left ( \frac{\Delta H_{vap}}{R}\right )\left ( \frac{1}{T_2}-\frac{1}{T_1}\right )[/tex]
i.e. it is independent of volume
As the temperature is not changed therefore vapor pressure remains same
The new vapor pressure of the liquid/vapor system is 11.87 torr.
The vapor pressure of the liquid/vapor system is determined by using general gas equation as shown below;
[tex]\frac{V_1P_1}{T_1} = \frac{V_2 P_2}{T_2} \\\\P_2 = \frac{V_1P_1T_2}{T_1V_2}, \ (T_1 = T_2)\\\\P_2 = \frac{V_1P_1}{V_2}\\\\P_2 = \frac{4 \times 26.7}{9} \\\\P_2 = 11.87 \ torr[/tex]
Thus, when the iquid/vapor equilibrium is reestablished, the new vapor pressure of the liquid/vapor system is 11.87 torr.
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