Respuesta :
Answer: There are 92 elements in A but not in B.
Step-by-step explanation:
Since we have given that
n(S) = 203
n(A) = 98
n(B) = 81
n(A∪ B) = 173
We first find the value of n(A∩B).
[tex]n(A\cup B)=n(A)+n(B)-n(A\cap B)\\\\173=98+81-n(A\cap B)\\\\173=179-n(A\cap B)\\\\173-179=-n(A\cap B)\\\\6=n(A\cap B)[/tex]
We need to find the number of elements that are in A but not in B.
[tex]n(A-B)=n(A)-n(A\cap B)\\\\n(A-B)=98-6\\\\n(A-B)=92[/tex]
Hence, there are 92 elements in A but not in B.
Answer:
92
Step-by-step explanation:
it is given that total number of elements =203
set A contains 98 that is A=98
set B contain 81 elements B=81
It is given that either A or B is 173
we know the formula
[tex]n\left ( A\cup B \right )=n(A)+n(B)-n(A\cap B)[/tex]
173=98+81 - Â [tex]n\left ( A\cap B \right )[/tex]
[tex]n\left ( A\cap B \right )[/tex] Â = Â 6
so the elements in A but not B =98-6=92
