Answer:[tex]frequency =\frac{1}{t}=\frac{1}{3.47\times 10^{-6}}=2.88\times 10^{5} Hz[/tex]
Explanation:
Given
B=[tex]1.03\times 10^{-5} T[/tex]
velocity[tex]\left ( v\right )=149 m/s[/tex]
mass of electron[tex]\left ( m\right )=9.11\times 10^{-31}[/tex]
charge on electron[tex]\left ( q\right )=1.6\times 10^{-19}[/tex]
We know[tex] r=\frac{mv}{qB}[/tex]
[tex]r=\frac{9.11\times 10^{-31}\times 149}{1.6\times 10^{-19}\times 1.03\times 10{-5}}[/tex]
[tex]r=8.23\times 10^{-5} m[/tex]
For frequency we need to know time period
[tex]t=\frac{2\pi r}{v}[/tex]
[tex]=\frac{2\times \pi \times 8.23\times 10^{-5}}{149}[/tex]
[tex]=3.47\times 10^{-6}[/tex]
[tex]frequency =\frac{1}{t}=\frac{1}{3.47\times 10^{-6}}=2.88\times 10^{5} Hz[/tex]
