Answer: 782
Step-by-step explanation:
Given : Mean : [tex]\mu=10.8[/tex]
Standard deviation : [tex]\sigma = 1.8[/tex]
Margin of error : [tex]E=0.15[/tex]
Significance level : [tex]\alpha=1-0.98=0.02[/tex]
Critical value : [tex]z_{\alpha/2}=2.33[/tex]
Formula for sample size :-
[tex]n=(\dfrac{z_{\alpha/2}\sigma}{E})^2\\\\\Rightarrow\ n=(\dfrac{2.33\times1.8}{0.15})^2=781.7616\approx782[/tex]
Hence, the minimum required sample size = 782
