Respuesta :
Explanation:
It is given that,
Length of wire, l = 20 km = 20,000 m
Velocity around earth, [tex]v=7.86\times 10^3\ m/s[/tex]
Earth's magnetic field, [tex]B=1.38\times 10^{-5}\ T[/tex]
Motional EMF is given by :
[tex]\epsilon=Blv\ sin\theta[/tex]
Where, [tex]\theta=90[/tex]
[tex]\epsilon=1.38\times 10^{-5}\times 20000\ \times 7.86\times 10^3\ sin(90)[/tex]
[tex]\epsilon=1939.4\ V[/tex]
So, the maximum possible potential difference (in V) between the two ends of the tether is 1939.4 V. Hence, this is the required solution.
The maximum possible potential difference (in V) between the two ends of the tether will be [tex]e=1939.4V[/tex]
What will be the maximum possible potential difference (in V) between the two ends of the tether?
It is given that
Length of the wire L= 20km=20000m
Velocity around the earth = [tex]7.86\times10^{3}\ \frac{m}{s}[/tex]
Earths magnetic [tex]1.38\times10^{-5}T[/tex]
The EMF will be given as
[tex]e=BLVsin\theta[/tex]
[tex]\theta=90[/tex]
put the values
[tex]e=1.38\times10^{-5}\times20000\times7.86\times10^3 sin(90)[/tex]
[tex]e=19.39.4V[/tex]
Thus the maximum possible potential difference (in V) between the two ends of the tether will be [tex]e=1939.4V[/tex]
To know more about Earths EMF follow
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