Answer:
2.1406 ×[tex]10^6[/tex] m/sec
Explanation:
we know that energy is always conserved
so from the law of energy conservation
[tex]qV=\frac{1}{2}mv^2[/tex]
here V is the potential difference
we know that mass of proton = 1.67×[tex]10^{-27}[/tex] kg
we have given speed =50000m/sec
so potential difference [tex]V=\frac{\frac{1}{2}\times 1.67\times 10^{-27}50000^2}{1.6\times 10^{-19}}=13.045[/tex]
now mass of electron =9.11×[tex]10^{-31}[/tex]
so for electron
[tex]\frac{1}{2}\times 9.11\times 10^{-31}v^2=1.6\times 10^{-19}\times 13.045=2.1406\times 10^6 m/sec[/tex]
so the velocity of electron will be 2.1406×[tex]10^6[/tex] m/sec
