If Jayden is reading a 275 page book and can read 10 pages in 15 minutes, skim through 15 pages in 10 minutes, and finishes the book in 5 hours and 50 minutes (reading and skimming combined), how many pages did Jayden have to skim through?

Respuesta :

Answer:

Jayden skimmed through 75 pages.

Step-by-step explanation:

Jayden is reading 275 page book.

Let Jyden read number of pages = x

and skimmed through pages = (275 -x)

Since Jayden read 10 pages in 15 minutes.

So time taken to read x pages = [tex]\frac{15\times x}{10}[/tex] minutes

and Jayden skim through 15 pages in 10 minutes

So time taken to skim (275-x) pages = [tex]\frac{10}{15}[/tex]× (275-x)

Now we know Jayden took total time to read and skim the book = 5 hours and 50 minutes.

so [tex]\frac{15}{10}x+ \frac{10}{15}(275-x)=350[/tex]

Multiply equation by 15.

22.5x + 10(275-x) = 350×15

22.5x + 2750 - 10x = 5250

12.5x = 5250 - 2750

12.5x = 2500

x = [tex]\frac{2500}{12.5}[/tex]

x = 200

Pages skimmed through = 275 - 200 = 75

Therefore, pages read by Jayden is 200 pages and skim through 75 pages.

Answer:

Jayden skim 75 pages.

Step-by-step explanation:

Consider the provided information.

First convert hours into minutes: 5 hours and 50 minutes can be written as:

5 × 60 + 50 = 350 minutes

let x is the number of minutes spent skimming. then the time spent in reading is (350-X).

He can read 10 pages in 15 minutes, skim through 15 pages in 10 minutes, and there are 275 page in book.

[tex]x\times \frac{15}{10}+ (350 - x) \times \frac{10}{15}= 275[/tex]

Now, solve for X.

[tex]x\times \frac{3}{2}+ (350 - x) \times \frac{2}{3}= 275[/tex]

[tex]\frac{9x+4(350-x)}{6}=275[/tex]

[tex]9x+1400-4x=1650[/tex]

[tex]5x=250[/tex]

[tex]x=50[/tex]

Hence, Jayden spent 50 minutes skimming.

The rate of 15 pages every 10 minutes, Thus the number of pages he skimmed is:

[tex]50\times \frac{15}{10}= 5\times 15=75[/tex]

Hence, he skim 75 pages.

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