Answer: The mass of nitrogen that is present for given amount of aluminium is 566.22 g.
Explanation:
We are given:
Mass of aluminium = 364 grams
The chemical formula of aluminium nitrate is [tex]Al(NO_3)_3[/tex]
Molar mass of nitrogen = 14 g/mol
Molar mass of aluminium = 27 g/mol
In 1 mole of aluminium nitrate, 27 grams of aluminium is combining with 42 grams of nitrogen.
So, 364 grams of aluminium will combine with = [tex]\frac{42}{27}\times 364=566.22g[/tex] of nitrogen.
Hence, the mass of nitrogen that is present for given amount of aluminium is 566.22 g.
