Answer:0.0203
Explanation:
Given
Fundamental frequency[tex]\left ( f_1\right ) =494 Hz[/tex]
[tex]\Delta f=5 beats/s[/tex]
[tex]f_2-f_1=5[/tex]
[tex]f_2=499 Hz[/tex]
[tex]f_1=\frac{1}{2l}\sqrt{\frac{T_1}{\mu }}---------1[/tex]
[tex]f_2=\frac{1}{2l}\sqrt{\frac{T_2}{\mu }}-------2[/tex]
Divide (1)&(2)
[tex]\frac{f_1}{f_2}=\sqrt{\frac{T_1}{T_2}}[/tex]
[tex]\frac{T_2}{T_1}=\left (\frac{f_2}{f_1} \right )^2[/tex]
[tex]\frac{T_2}{T_1}-1=\left (\frac{f_2}{f_1} \right )^2-1[/tex]
[tex]\frac{T_2}{T_1}-1=0.0203[/tex]
