Answer:
6m+7.5
Step-by-step explanation:
the arithmetic mean is the average of two numbers
it is given that a is average of 6m and 10
so [tex]a=\frac{6m+10}{2}[/tex]
b is the average of 4m and 4
so [tex]b=\frac{4m+4}{2}[/tex]
c is the average of 14m and 16
so [tex]c=\frac{14m+16}{2}[/tex]
now the average of a ,b and c is given by
[tex]average=\frac{a+b+c}{3}=\frac{\frac{6m+10}{2}+\frac{4m+4}{2}+\frac{14m+16}{2}}{3}=6m+7.5[/tex]
