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A particle with a mass of 2.3 × 10-20 kg is oscillating with simple harmonic motion with a period of 3.0 × 10-5 s and a maximum speed of 2.2 × 103 m/s. Calculate (a) the angular frequency and (b) the maximum displacement of the particle.

Respuesta :

Answer:

angular frequency is 209439.51 rad/sec

maximum displacement  is 0.010504 m

Explanation:

Given data

mass = 2.3 × 10^-20 kg

period = 3.0 × 10^-5 s

maximum speed = 2.2 × 10^3 m/s

to find out

the angular frequency and  maximum displacement

solution

we know angular frequency formula that is

angular frequency = 2 π / period

put here period value we get angular frequency

angular frequency = 2 π / 3.0 × 10^-5

angular frequency is 209439.51 rad/sec

maximum displacement formula is

speed = angular frequency × maximum displacement

put all value and we get maximum displacement

maximum displacement  = 2.2 × 10^3 / 209439.51  

maximum displacement  is 0.010504 m

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