Answer:
Step-by-step explanation:
I urn: 3 blue 7 red
II urn: 7 blue and 3 red
When draw is done with replacement no of red or blue will be binomial with equal probability for each trial
Let B = draw yielded 8 reds and 4 blues.
A1= Drawn from I urn
A2 = Drawn from II urn
A1 and A2 are mutually exclusive and exhaustive
Required probability = P(A1/B) = [tex]\frac{P(A1B)}{P(A1B)+P(A2B)}[/tex]
P(A1B) = [tex](\frac{7}{10} )^8*(\frac{3}{10} )^4\\=\frac{7^8(3^4)}{10^{12} }[/tex]
P(A2B) = [tex](\frac{3}{10} )^8(\frac{7}{10} )^4\\=\frac{3^8(7^4)}{10^{12} }[/tex]
P(A1/B) =[tex]\frac{7^8(3^4)}{7^8(3^4+3^8(7^4)}[/tex]