Answer:
162.78 m/s is the most probable speed of a helium atom.
Explanation:
The most probable speed:
[tex]v_{mp}=\sqrt{\frac{2K_bT}{m}}[/tex]
[tex]K_b[/tex]= Boltzmann’s constant =[tex]1.38066\times 10^{-23} J/K[/tex]
T = temperature of the gas
m = mass of the gas particle.
Given, m = [tex]6.65\times 10^{-27} kg[/tex]
T = 6.4 K
Substituting all the given values :
[tex]v_{mp}=\sqrt{\frac{2\times 1.38066\times 10^{-23} J/K\times 6.4 K}{6.65\times 10^{-27} kg}}[/tex]
[tex]v_{mp}=162.78 m/s[/tex]
162.78 m/s is the most probable speed of a helium atom.
