Answer:
Let the weight of the person be W and be located at a distance 'a' from the left scale as shown in the figure
Since the body is in equilibrium we can use equations of statics to analyse the problem.
Taking Sum of Moments about A we have
[tex]316\times 1.71-W\times a=0\\\\[/tex]
Taking Sum of Moments about B we have
[tex]475\times 1.71-W\times (1.71-a)=0\\\\[/tex]
Solving the above 2 equations for W and 'a' we get
[tex]316\times 1.71=W\times a\\\\475\times 1.71-W\times 1.71=-Wa\\\\\therefore W=\frac{316+475}{1}=791N\\\\\therefore a=\frac{316\times 1.71}{791}=0.683m[/tex]
