Answer:
The remainder is 28x+30
Step-by-step explanation:
We will divide 3x^3-2x^2+4x-3 by x^2+3x+3.
To get the first term of the dividend we will multiply x^2+3x+3 by 3x
3x(x^2+3x+3)
=3x^3+9x^2+9x
It means
x^2+3x+3) 3x^3-2x^2+4x-3( 3x -11
3x^3+9x^2+9x
- - -
_________________
11x^2-5x-3 (Now multiply x^2+3x+3 by -11 to get the
11x^2-33x-33 first term)
- + +
_______________
28x+30
We can not solve it further because remainder has two terms and divisor has 3 terms. Therefore the remainder is 28x+30....
