Answer:
E=0
Explanation:
According to Gauss law:
[tex]\int E.dA =\frac{Q_{en}}{\epsilon_o}[/tex]
So, first calculate the amount of charge enclosed in the region where r < R₁.
Since, the volume charge density is just throughout the shell (i.e. between R₂ and R₁), there is no charge in the region r < R₁. Therefore, [tex]{Q_{en}=0[/tex]
⇒ E = 0 for r < R₁