Answer:
d = 0.286 mm
Explanation:
from single silt diffraction pattern we have
[tex]y =\frac{m\lambda D}{d}[/tex]
difference in y between first and second minima isgiven as
[tex]y_2 -y_1 = \frac{2*633*10^{-9}1.80}{d} - \frac{1*633*10^{-9}1.80}{d}[/tex]
[tex] = \frac{1.13*10^{-6}}{d}[/tex] m
but we have
[tex]y_2 -y_1 = 3.95[/tex]
[tex]\frac{1.13*10^{-6}}{d} = 3.95*10^{-3}m[/tex]
d = 2.86*10^{-4} m
d = 0.286 mm
