Answer:
The time is 0.5 sec.
Explanation:
Given that,
Voltage V= 12.00 V
Inductance L= 1.20 H
Current = 3.00 A
Increases rate = 8.00 A
We need to calculate change in current
[tex]\Delta A = 8.00-3.00= 5.00\ A[/tex]
We need to calculate the time interval
Using formula of inductor
[tex]V=L\dfrac{\Delta A}{\Delta t}[/tex]
[tex]\Delta t =\dfrac{L\Delta A}{V}[/tex]
Where, [tex]\Delta A[/tex] = change in current
V = voltage
L = inductance
Put the value into the formula
[tex]\Delta t=\dfrac{1.20\times5.00}{12.00}[/tex]
[tex]\Delta t=0.5\ sec[/tex]
Hence, The time is 0.5 sec.
