Answer: 94.09%
Step-by-step explanation:
Binomial probability formula :-
[tex]P(x)=^nC_xp^x(1-p)^{n-x}[/tex], where P(x) is the probability of getting success in x trials , n is number of trials and p is the probability of getting success in each trial.
Given : The probability that the any of the three major components of a computer is defective =0.03
Now, the probability that no more than one component is defected in a computer set :-
[tex]P(x\leq1)=P(0)+P(1)\\\\=^3C_0(0.03)^0(0.97)^3+^3C_1(0.03)^1(0.97)^2\\\\=(0.97)^3+(0.03)^1(0.97)^2=0.9409=94.09\%[/tex]
Hence, the chance that no more than one component is defected in a computer set is 94.09% .
