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A coaxial cable consists of an inner conductor with radius ri = 0.20 cm and an outer radius of ro = 0.4 cm and has a length of 13 meters. Plastic, with a resistivity of ρ = 2.00 ✕ 1013 Ω · m, separates the two conductors. What is the resistance (in Ω) of the plastic when current is flowing between the two conductors of the coaxial cable?

Respuesta :

Answer:

[tex]R = 1.69*10^{11} ohm[/tex]

Explanation:

ri = 0.20cm

ro = 0.4 cm

length L = 13m

resistivity \rho = 2.00*10^13 ohm m

resistance can be determine by using following relation

[tex]R = \frac{\rho}{2\pi L} ln\frac{ro}{ri}[/tex]

[tex]R = \frac{2.00*10^{13}}{2\pi *10} ln\frac{.004}{.002}[/tex]

[tex]R = 1.69*10^{11} ohm[/tex]

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