50. A bag contains five yellow tickets numbered one to five. The bag also contains five green tickets numbered one to five. You randomly pick a ticket. It is green or has a number greater than four. Find the probability of this occuring. (2.0 Points)

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Answer:

60%

Step-by-step explanation:

There is a one in two chance of picking up a green ticket, since there are only two colours. The only number greater than 4 in this pack is 5. The chances of picking up a five are 2 out of 10. The chances of picking up a green 5 is 1 out of 10.

These events aren't mutually exclusive, because you can pick up a green 5 , which would constitute both events.

The probability of an OR function of events which aren't mutually exclusive is as follows:

[tex]P(A or B) = P(A) + P(B)-P(A and B).[/tex]

Where:

A: green card

B: number 5 card

C: number 5 green card.

Thus:

[tex]P(A or B)=\frac{5}{10} +\frac{2}{10} -\frac{\frac{x}{y} 1}{10} \\\\P(A or B)=\frac{6}{10} =0.6[/tex]

The probability of this occurring is 60%.

Given

A bag contains five yellow tickets numbered one to five.

The bag also contains five green tickets numbered one to five.

You randomly pick a ticket. It is green or has a number greater than four.

What is the probability?

When an event is certain to happen then the probability of occurrence of that event is 1 and when it is certain that the event cannot happen then the probability of that event is 0.

The probability of picking a green card is 5/10.

The probability of picking a number 5 card is 2/10.

The probability of picking number 5 green card is 1/10.

Therefore,

The probability of this occurring is;

[tex]\rm =\dfrac{5}{10}+\dfrac{2}{10}-\dfrac{1}{10}\\\\= \dfrac{5+2-1}{10}\\\\= \dfrc{6}{10}\\\\=0.06\\\\= 60 \ percent[/tex]

Hence, the probability of this occurring is 60%.

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