Answer:
the index of refraction for the transparent material is 1.48
Explanation:
let n1 = 1.0 be the refractive index of air and n2 be the refractive index of the trasnparent material.
then:
Snell's Law state that:
n1×sin(∅1) = n2×sin(∅2)
where ∅1 = 56.0° is the angle of incidence and ∅2 = 90 - 56.0 = 34° be the angle refraction.
n1×sin(∅1) = n2×sin(∅2)
n2 = n1×sin(∅1)/sin(∅2)
= (1.0)×sin(56.0°)/sin(34.0°)
= 1.48
Therefore, the index of refraction for the transparent material is 1.48
