Respuesta :
Answer:
The weight corresponding to which weight will be larger than 14% of times equals 427.635 grams.
Step-by-step explanation:
We need to find the value of weight that corresponds to 14% of area under the normal distribution curve
It is given that
[tex]\overline{X}=446\\\\\sigma =17[/tex]
Using standard normal distribution tables we find value of Z corresponding to 14% of the area as -1.080
Thus using the standard equation
[tex]Z=\frac{X-\overline{X}}{\sigma }\\\\X=\sigma \times Z+\overline{X}\\\\\therefore X=427.635grams[/tex]
Answer:
weight will be greater by 20 gm.
Step-by-step explanation:
to calculate the z score use negative z table for 0.14
P ( Z < x ) = 0.86
Value of z to the cumulative probability of 0.86 from normal table is 1.18
mean(μ) = 446 gm
standard deviation(σ) = 17 grams
[tex]z=\dfrac{x-\mu}{\sigma} \\1.18=\dfrac{x-446}{17}\\x = 466.06[/tex]
hence the weight will be greatest by
= 466 - 446 = 20 gm
