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A 1790 kg car has just passed a diner. The closest the car came to the diner was R=28.5 m , but the car has driven another x=42.7 m in the 2.85 s2.85 s elapsed since then. If the car travels at constant speed, what is the current magnitude of the angular momentum of the car about the diner?

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Karabo99

Answer:

6208270.4 kg.m^2/s^1

Explanation:

let X = x = 42.7 m and t = 2.85s

the speed of the car, v = X×t

                                      = 42.7×2.85

                                      = 121.695 m/s

then, we know that the angular momentum is given by:

when the is just passing the dinner, the distance from the diner to the car is perpendicular to the cars trajectory.

L = m×R×v , where R is the perpendicular distance.

  =  1790×28.5×121.695

  = 6208270.4 kg.m^2/s^1

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