Answer:
probability comes out to be [tex]\dfrac{5}{1296}[/tex]
Step-by-step explanation:
when the dice is singly rolled
chances of getting 4 (Y)is [tex]\dfrac{1}{6}[/tex]
and,
chance of not getting 4 (N) is [tex]\dfrac{5}{6}[/tex]
probability of getting 4 on first, second and third time and not on the forth time is
P( Y, Y, Y, N ) = [tex]\dfrac{1}{6} \times \dfrac{1}{6} \times \dfrac{1}{6} \times \dfrac{5}{6}[/tex]
= [tex]\dfrac{5}{1296}[/tex]
so the probability comes out to be [tex]\dfrac{5}{1296}[/tex]
