A metal, M, of atomic weight 96 reacts with fluorine to form a salt that can be represented as MFx. In order to determine x and therefore the formula of the salt, a boiling point elevation experiment is performed. A 9.18-g sample of the salt is dissolved in 100.0 g of water and the boiling point of the solution is found to be 374.38 K.
(A) MF
(B) MF2
(C) MF3
(D) MF4

Respuesta :

Answer:

The correct answer is option 3.

Explanation:

Molecular formula of the salt =[tex]MF_x[/tex]

The salt when dissolved in water will get dissociated into ions.

[tex]MF_x\rightarrow M^{x+}+xF^-[/tex]

van't Hoff factor = i = 1+x

Boiling point of the solution = [tex]T_b=374.38 K[/tex]

Boiling point of pure solvent that water = [tex]T=373.15 K[/tex]

Elevation in boiling point =[tex]\Delta T_b[/tex]

[tex]\Delta T_b=T_b-T=374.38 K-373.15 K=1.23 K[/tex]

[tex]\Delta T_b=i\times K_b\times m[/tex]

[tex]K_b[/tex]=molal elevation constant

m = molality of the solution

Molal elevation constant of water =0.52 K kg/mol

molality = [tex]\frac{\text{Mass of compound}}{\text{Molar mass of compound}\times \text{mas of solvent in kg}}[/tex]

[tex]m=\frac{9.18 g}{(96 g/mol+x\times 19 g/mol)\times 0.100 kg}[/tex]

[tex]1.23 K=i\times 0.52 K kg/mol\times \frac{9.18 g}{(96 g/mol+x\times 19 g/mol)\times 0.100 kg}[/tex]

i = 2.47+0.48x

2.47+0.48x = 1+x

x =2.8 ≈ 3

Molecular formula of the salt =[tex]MF_3[/tex]

Q&A Education