Answer:
The speed of the ambulance is 4.30 m/s
Explanation:
Given:
Frequency of the ambulance, f = 1790 Hz
Frequency at the cyclist, f' = 1780 Hz
Speed of the cyclist, vâ‚€ = 2.36 m/s
let the velocity of the ambulance be 'vâ‚“'
Now,
the Doppler effect is given as:
[tex]f'=f\frac{v\pm v_o}{v\pm v_x}[/tex]
where, v is the speed of sound
since the ambulance is moving towards the cyclist. thus, the sign will be positive
thus,
[tex]v_x=\frac{f}{f'}(v+v_o)-v[/tex]
on substituting the values, we get
[tex]v_x=\frac{1790}{1780}(343+2.36)-343[/tex]
or
vâ‚“ = 4.30 m/s
Hence, the speed of the ambulance is 4.30 m/s
