Answer:
D
Step-by-step explanation:
We can multiply the first fraction by the reciprocal of the second to get
[tex]\frac{3x*(x-2)}{6x^2*(2x-4)}[/tex]
Taking out the 2 from the denominator, we get
[tex]\frac{3x*(x-2)}{6x^2*2(x-2)}[/tex]
Canceling the (x-2) from the top and bottom gives us
[tex]\frac{3x}{6x^2*2}[/tex] or [tex]\frac{3x}{12x^2}[/tex]
Now, dividing top and bottom by 3x gives us [tex]\frac{1}{4x}[/tex], or D
