Answer:
limiting reagent is given by
Answer:
The Thermite Reaction is
[tex]2Al(s)+Fe_2 O_3 (s)>2Fe(l)+Al_2 O_3 (s)[/tex]
The conversions are
mass [tex]Fe_2 O_3[/tex] to moles [tex]Fe_2 O_3[/tex]to moles Fe to mass Fe
[tex]$1.873 \times 10^{2} g \mathrm{Fe}_{2} \mathrm{O}_{3} \times \frac{1 \mathrm{mol} \mathrm{Fe}_{2} \mathrm{O}_{3}}{159.7 \mathrm{g} \mathrm{Fe}_{2} \mathrm{O}_{3}} \times \frac{2 \mathrm{molFe}}{1 \mathrm{mol} \mathrm{Fe}_{2} \mathrm{O}_{3}} \times \frac{55.85 \mathrm{g} \mathrm{Fe}}{1 \mathrm{mol} \mathrm{Fe}}$[/tex]
=131 g Fe is obtained
mass Al to moles Al to moles Fe to mass Fe
[tex]$94.51 g A l \times \frac{1 m o l A l}{26.98 g A l} \times \frac{2 m o l F e}{2 m o l A l} \times \frac{55.85 g F e}{1 m o l f e}$[/tex]
=196 g Fe is obtained
The reactant which runs out first is called as Limiting reactant.
Less mass of the Product is obtained from the limiting reactant.
So we see here [tex]Fe_2 O_3[/tex] produces less product (131g Fe) than the product produced by Al (196 g Fe)
Hence [tex]Fe_2 O_3[/tex] (Answer) is the Limiting reactant and it runs out first
