Respuesta :
namely, what is the leftover amount when the decay rate is 2% for an original amount of 75 grams after 10 years?
[tex]\bf \qquad \textit{Amount for Exponential Decay} \\\\ A=P(1 - r)^t\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &75\\ r=rate\to 2\%\to \frac{2}{100}\dotfill &0.02\\ t=\textit{elapsed time}\dotfill &10\\ \end{cases} \\\\\\ A=75(1-0.02)^{10}\implies A=75(0.98)^{10}\implies A\approx 61.28\implies \stackrel{\textit{rounded up}}{A=61~grams}[/tex]
Answer with explanation:
The exponential decay function is written as :-
[tex]f(x)=A(1-r)^x[/tex], where f (x) is the amount of material left after x years , A is the initial amount of material and r is the rate of decay.
Given : The amount of original item remained now = 75 grams
The rate of decay = 2% = 0.02
Now, the amount of original artifact would there be left if they had not discovered it for another 10 years is given by :-
[tex]f(10)=75(1-0.02)^{10}[/tex]
Solving the above exponential equation , we get
[tex]=61.2804605166\approx61[/tex]
Hence only 61 grams original artifact would there be left if they had not discovered it for another 10 years .