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Two slits are illuminated by a 602 nm light. The angle between the zeroth-order bright band at the center of the screen and the fourth-order bright band is 17.4 ◦ . If the screen is 138 cm from the double-slit, how far apart is this bright?

Respuesta :

Answer:

y = 43.2 cm

Explanation:

As we know by the formula of diffraction we have

[tex]a sin\theta = N\lambda[/tex]

here we have

[tex]\theta = 17.4[/tex]

N = 4

[tex]\lambda = 602 nm[/tex]

now we have

[tex]a sin(17.4) = 4(602\times 10^{-9})[/tex]

[tex]a = 8.05 \times 10^{-6} m[/tex]

now the distance of screen is 138 cm

now we can say

[tex]\frac{y}{L} = tan\theta[/tex]

[tex]y = L tan(\theta)[/tex]

[tex]y = 138 tan(17.4) = 43.2 cm[/tex]

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