Answer:
d. no real solutions
Step-by-step explanation:
3p − 9p² = 6
0 = 9p² − 3p + 6
0 = 3p² − p + 2
The discriminant of ax² + bx + c is b² − 4ac.
If the discriminant is negative, there are no real roots.
If the discriminant is zero, there is 1 real root.
If the discriminant is positive, there are 2 real roots.
If the discriminant is a perfect square, the root(s) are rational.
If the discriminant isn't a perfect square, the root(s) are irrational.
Finding the discriminant:
a = 3, b = -1, c = 2
(-1)² − 4(3)(2) = -23
The discriminant is negative, so there are no real roots.
