If the intensity of an electromagnetic wave is 80 MW/m2, what is the amplitude of the magnetic field of this wave? (c=3.0×108m/s, μ0=4π×10−7T⋅m/A, ε0=8.85×10−12C2/N⋅m2)

Respuesta :

Answer:

The the amplitude of the magnetic field of this wave is [tex]2.4\times10^{5}\ N/C[/tex]

Explanation:

Given that,

Intensity [tex]S= 80 Mw/m^2[/tex]

We need to calculate the amplitude of the magnetic field

Using formula of intensity

[tex]S=\dfrac{E_{m}^2}{2c\mu_{0}}[/tex]

Where, [tex]E_{m}[/tex]=Amplitude of an electromagnetic wave

c = speed of light

Put the value into the formula

[tex]E_{m}^2=80\times10^{6}\times2\times3\times10^{8}\times4\pi\times10^{-7}[/tex]

[tex]E_{m}=245598.40\ N/C[/tex]

[tex]E_{m}=2.4\times10^{5}\ N/C[/tex]

Hence, The the amplitude of the magnetic field of this wave is [tex]2.4\times10^{5}\ N/C[/tex]  

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