Respuesta :

carlosego

For this case we have a fucnion of the form [tex]y = f (x)[/tex]

Where:

[tex]f (x) = 4x-1[/tex]

By definition, the rank of a function is given by:

The set of the real values that the variable y or f (x) takes.

So:

[tex]f (-1) = 4 (-1) -1 = -4-1 = -5\\f (0) = 4 (0) -1 = 0-1 = -1\\f (1) = 4 (1) -1 = 4-1 = 3\\f (2) = 4 (2) -1 = 8-1 = 7\\f (3) = 4 (3) -1 = 12-1 = 11[/tex]

ANswer:

The range is: -5, -1,3,7,11

wegnerkolmp2741o

Answer:

{-5,-1,3,7,11}

Step-by-step explanation:

The range is the output of the function

We have the inputs

f(x) = 4x - 1

f(-1) = 4(-1)-1 = -4-1 = -5

f(0) = 4(0)-1 = 0-1 = -1

f(1) = 4(1)-1 = 4-1 = 3

f(2) = 4(2)-1 = 8-1 = 7

f(3) = 4(3)-1 = 12-1 = 11

The outputs for the given inputs are

{-5,-1,3,7,11}

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