Student prepares a 0.207 g sample of the nonvolatile solute caryophyllene by dissolving the substance in 1.00 g of chloroform (Kb = 3.63C/m). The boiling point of chloroform increases by 3.68C. Determine the molar mass (g/mol) of caryophyllene?

Respuesta :

Answer: 204.2 g/mol

Explanation:

Elevation in boiling point is given by:

[tex]\Delta T_b=k_b\times m[/tex]

[tex]\Delta T_b[/tex] =  Elevation in boiling point =  [tex]3.68^0C/m[/tex]

[tex]k_b[/tex] = boiling point constant  = [tex]3.63^0C/m[/tex]

m = molality

[tex]Molality=\frac{n\times 1000}{W_s}[/tex]

where,

n = moles of solute = [tex]\text {given mass}{\text {molar mass}}=\frac{0.207}{M}[/tex]

 [tex]W_s[/tex] = weight of solvent in g  = 1g

Molality =[tex]\frac{0.207\times 1000}{M\times 1g}[/tex]

Putting in the values we get,

[tex]3.68=3.63\times \frac{0.207\times 1000}{M\times 1g}[/tex]

[tex]M=204.2g/mol[/tex]

The molar mass of caryophyllene is 204.2 g/mol.

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