It takes 155. Kj/mol to break a fluorine-fluorine single bond. Calculate the maximum wavelength of light for which a flouine-flouring single bond could be broken by absorbing a single photon

Respuesta :

Answer:

The maximum wavelength of light will be 773.46 nm.

Explanation:

Energy required to break a fluorine-fluorine single bond = 155 kJ/mol

For 1 mole of fluorine gas  = 155 kJ = 155000 J

For [tex]6.022\times 10^{23}[/tex] molecules = 155000 J

Then energy to break 1 molecule = [tex]\frac{155000 J}{6.022\times 10^{23}}=2.57\times 10^{-19} J[/tex]

Energy of the photon E =[tex]2.57\times 10^{-19} J[/tex]

Wavelength of the light =[tex]\lambda [/tex]

[tex]E=\frac{hc}{\lambda }[/tex]

[tex]2.57\times 10^{-19} J=\frac{6.626\times 10^{-34} Js\times 3\times 10^8 m/s}{\lambda }[/tex]

[tex]\lambda =7.7346\times 10^{-7} m=773.46 nm[/tex]

The maximum wavelength of light will be 773.46 nm.

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