Answer:
y = 1
Step-by-step explanation:
Given function is:
[tex]\frac{x^2+8x+3}{x^2+3x+1}[/tex]
In order to find the horizontal asymptote, the coefficients of highest degree variable of numerator and denominator are divided.
In our case,
both the numerator and denominator have 1 as he co-efficient of x^2
So the horizontal asymptote is y = 1/1
Hence, third option y=1 s correct ..