Respuesta :
Answer:
[tex]9,03.10x^{24}[/tex] molecules of [tex]O_2[/tex]
Explanation:
We have the following balanced equation
[tex]P_4+5O_2 \longrightarrow 2P_2O_5[/tex]
According to the stoichiometric coefficients of the reagents for each mole of [tex]P_4[/tex], 5 moles of [tex]O_2[/tex] are needed,
We apply a simple three rule to find out how many moles of O2 are required for 3 moles of P4 to react
[tex]1 mol P_4 \longrightarrow 5 mol O_2\\3 mol P_4\longrightarrow x \\x=\frac{(3molP_4)(5molO_2)}{1molP_4} \\x= 15 molO_2[/tex]
Now we know that we need 15 moles of [tex]O_2[/tex] so that 3 moles of [tex]P_4[/tex] reactions
Remember that 1 mole (of any element or substance) is equal [tex]6,02.10^{23}[/tex] molecules
To find out how many molecules of O2 are required we apply a simple rule of three
[tex]1 mol O_2 \longrightarrow6,02.10^{23}molecules \\15 molO_2 \longrightarrow x \\x=\frac{(15molO_2)(6,02.10^{23}molecules)}{1molO_2} \\x=9,03.10^{24} molecules[/tex]
To react 3 moles of[tex]P_4[/tex], [tex]9,03.10^{24}[/tex] molecules of [tex]O_2[/tex] are required
