A rock climber throws a small first aid kit to another climber who is higher up the mountain. The initial velocity of the kit is 5.70 m/s at an angle of 45.7 ° above the horizontal. At the instant when the kit is caught, it is traveling horizontally, so its vertical speed is zero. What is the vertical height between the two climbers?

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Blacklash Blacklash · Answer 1 · 2019-07-13T09:55:53+02:00

Answer:

Height difference between climbers = 0.85 m.

Explanation:

Vertical motion of first aid kit:

Initial vertical velocity, u = 5.70 sin 45.7 = 4.08 m/s

Acceleration, g = -9.81 m/s²

When the climber who is higher up the mountain catches the kit it's vertical speed is zero.

Final vertical velocity, v = 0 m/s

We have equation of motion, v² = u² + 2as

Substituting

0² = 4.08² + 2 x -9.81 x s

s = 0.85 m

So the kit travels 0.85 m vertically.

Height difference between climbers = 0.85 m.