Answer: 0.3446
Step-by-step explanation:
Given  : Mean : [tex]\mu = 90[/tex]
Standard deviation : [tex]\sigma = 10[/tex]
Also, the reading speed of second grade students in a large city is approximately​ normal.
Then , the formula to calculate the z-score is given by :_
[tex]z=\dfrac{x-\mu}{\sigma}[/tex]
For x = Â 94
[tex]z=\dfrac{94-90}{10}=0.4[/tex]
The p-value = [tex]P(z>0.4)=1-P(z<0.4)=1-0.6554217[/tex]
[tex]\\\\=0.3445783\approx0.3446[/tex]
Hence, the  probability a randomly selected student in the city will read more than 94 words per​ minute =0.3446
