Answer:
12.1%
Step-by-step explanation:
First calculate the z-score:
z = (x − μ) / σ
z = (55000 − 48000) / 6000
z = 1.17
Look up in a z-score table.
P(z>1.17) = 1 − 0.8790
P(z>1.17) = 0.1210
There's a 12.1% probability that a randomly selected individual with a master's in statistics will have a starting salary of at least $55,000.