Respuesta :
Answer:
The formula of the hydrate of the sodium sulfate is :[tex]Na_2SO_4.7H_2O[/tex]
Explanation:
Mass of hydrated sodium sulfate = 40.15 gram
Mass of completely dehydrated sodium sulfate = 21.27 gram
Mass of water molecules present in hydrated sodium sulfate =x
40.15 gram = 21.27 gram + x (Law of conservation of mass)
x = 40.15 gram - 21.27 gram = 18.88 g
Moles of water = [tex] \frac{18.88 g}{18 g/mol}= 1.04mol[/tex]
Moles of sodium sulfate =[tex]\frac{21.27 g}{142.04 g/mol}=0.1497 mol[/tex]
Whole number ratio of sodium sulfate and water:
Sodium sulfate =[tex]\frac{0.1497 mol}{0.1497 mol}=1[/tex]
Water =[tex]\frac{1.04 mol}{0.1497 mol}=6.9 a\\rox 7[/tex]
The formula of hydrate be [tex]Na_2SO_4.7H_2O[/tex]
So, the formula of the hydrate of the sodium sulfate is :[tex]Na_2SO_4.7H_2O[/tex]
