What is the area of the rhombus shown below? MK=13 JL= 17
Answer:
110.5 units²
Step-by-step explanation:
The area (A) of a rhombus is calculated as
A = [tex]\frac{1}{2}[/tex] product of diagonals, that is
A = 0. 5 × MK × JL = 0.5 × 13 × 17 = 110.5
The area of the rhombus will be 110.5 square units.
The area of the rhombus can be calculated by half of the product of its two diagonals.
Here given,
JKLM is a rhombus.
The length of its diagonals will be MK=13
JL=17
The diagonal MK and JL intersect each other by 90° at point O.
Now the rhombus is divided by 4 right-angled triangle,
Area of the rhombus will be 4 times of the right-angled triangle ΔMJO
Area of the rhombus= 4*Area of right-angled triangle ΔMJO
=4*(1/2)*MO*JO
= 4*(1/2)*(MK/2)(JL/2)
=(1/2)*MK*JL
=(1/2)*the product of its two diagonals
=(1/2)*13*17
=110.5 Square unit
Therefore the area of the rhombus will be 110.5 square units.
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