Respuesta :
Explanation:
Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as [tex]K_{eq}[/tex]
For a general chemical reaction:
[tex]aA+bB\rightarrow cC+dD[/tex]
The expression for [tex]K_{eq}[/tex] is written as:
[tex]K_{eq}=\frac{[C]^c[D]^d}{[A]^a[B]^b}[/tex]
Concentration of solid substances in a chemical reaction is taken to be 1.
- For a: [tex]2Cr^{3+}(aq.)+3Sn(s)\rightarrow 2Cr(s)+3Sn^{2+}(aq.)[/tex]
The expression of equilibrium constant for above equation follows:
[tex]K_{eq}=\frac{[Sn^{2+}]^3}{[Cr^{3+}]^2}[/tex]
Concentration of chromium and tin are taken to be 1 because they are present in solid phase. So, they will not appear in the equilibrium constant expression.
- For b: [tex]O_2(g)+2H_2O(l)+2Sn^{2+}(aq.)\rightarrow 4OH^-(aq.)+2Sn^{4+}(aq.)[/tex]
The expression of equilibrium constant for above equation follows:
[tex]K_{eq}=\frac{[Sn^{4+}]^2[OH^-]^4}{[Sn^{2+}]^2[H_2O]^2[O_2]}[/tex]
- For c: [tex]2Cr^{3+}(aq.)+3Ni(s)\rightarrow 2Cr(s)+3Ni^{2+}(aq.)[/tex]
The expression of equilibrium constant for above equation follows:
[tex]K_{eq}=\frac{[Ni^{2+}]^3}{[Cr^{3+}]^2}[/tex]
Concentration of chromium and nickel are taken to be 1 because they are present in solid phase. So, they will not appear in the equilibrium constant expression.
The equilibrium constant for each of the reactions at 25 degree C are [Sn₂²⁺]³/ [Cr³⁺]², [OH⁻]⁴[Sn⁴⁺]² / [Sn²⁺]²[O₂] & [Ni²⁺]³ / [Cr³⁺]² respectively.
How we calculate Equilibrium constant?
Equilibrium constant of any reaction is define as the ratio of the concentration of the product to the concentration of reactant, which having the power of respective stoichiometry coefficient.
In the equilibrium equation value of the pure solids and liquids is always one.
(a). Given chemical reaction is:
2Cr³⁺(aq) + 3Sn(s) ⇄ 2Cr(s)+3Sn²⁺(aq)
Equilibrium constant = [Sn₂²⁺]³/ [Cr³⁺]²
(b). Given chemical reaction is:
O₂(g) + 2H₂O(l) + 2Sn²⁺(aq) ⇄ 4OH⁻(aq) + 2Sn⁴⁺(aq)
Equilibrium constant = [OH⁻]⁴[Sn⁴⁺]² / [Sn²⁺]²[O₂]
(c). Given chemical reaction is:
2Cr³⁺(aq) + 3Ni(s) ⇄ 2Cr(s) + 3Ni²⁺(aq)
Equilibrium constant = [Ni²⁺]³ / [Cr³⁺]²
Hence, the value of equilibrium constant are [Sn₂²⁺]³/ [Cr³⁺]², [OH⁻]⁴[Sn⁴⁺]² / [Sn²⁺]²[O₂] & [Ni²⁺]³ / [Cr³⁺]².
To know more about Equilibrium constant, visit the below link:
https://brainly.com/question/14095591
